Triangle ABC is graphed below with vertices at A (-4,5), B (-6, -4) and C (4,-4). Use the following rule to produce triangle A'B'C' using ABC as the original image.
F(x, y) — (x+2, -y)
Show Your Work
Someone help me to solve this problem asap! Please

Step-by-step explanation:

A(-4, 5) => A'(-4+2, -5) = A'(-2, -5)

B(-6, -4) => B'(-6+2, -(-4)) = B'(-4, 4)

C(4, -4) => C'(4+2, -(-4)) = C'(6, 4)

Hence the new coordinates are A'(-2, -5), B'(-4, 4) and C'(6, 4).

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560

none.

step-by-step explanation:

m

1

=

5

m1=5

b

=

−

1

b=-1

find the slope and y-intercept of the second equation.

tap for more

m

2

=

0

m2=0

b

=

−

6

b=-6

compare the slopes

m

m of the two equations.

m

1

=

5

,

m

2

=

0

m1=5,m2=0

compare the two slopes in the decimal form. if the slopes are equal, then the lines are parallel. if the slopes are not equal, then the lines are not parallel.

m

1

=

5

,

m

2

=

0

m1=5,m2=0