3×-5=16 and 3×=21 the first equation is a true statement for a certain value of x.

can you explain why the second equation must also be true for the same value of x?

We conclude that x = 7 must be true for the second equation because it will also satisfy the second equation.

Step-by-step explanation:

Given the first equation

solving the equation

3x-5 = 16

adding 5 to both sides

3x-5+5 = 16+5

3x = 21        ∵ 3x = 21 is the 2nd equation      

divide bothe sides by 3

3x/3 = 21/3

x = 7

Please notice that when simplifying 3x-5 = 16, the moment we reach 3x=21, we can determine that it represents the same equation.

In other words, whatever the value of x we will get, it will satisfy both equations.

Therefore, we conclude that x = 7 must be true for the second equation because it will also satisfy the second equation.

Verification:

Consider the 2nd equation

3x = 21

Put x = 7

3(7) = 21

21 = 21

Thus, it has been validated that when we conclude that x = 7 must be true for the second equation because it will also satisfy the second equation.

i dont know

step-by-step explanation:

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length