Ed wants to build a small 800 square foot cabin on a lot that is 80 feet deep. If the building sideyard setbacks are 20 feet and the cabin is 20 feet wide, what is the square footage of the lot

4800 ft²

Step-by-step explanation:

Given that :

Area of cabin = 800 ft²

Width of cabin = 20 feets

Side yard setback of building = 20 feets

Depth of lot = 80 feets

The cabin is a rectangle :

Area of rectangle = Length * Width

800 = length * 20

Length = 800 / 20 = 40 feets

Hence,

Width of lot = side yard + Width of cabin = (20 + 20) = 40 feets

Length of lot = depth +. Length of cabin = (80 + 40) = 120 feets

Area of lot = Length of lot * width of lot

Area of lot = 120 ft * 40 ft = 4800 ft²

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

step-by-step explanation: i dont