To test whether an integer, $n$, is prime, it is enough to be sure that none of the primes less than or equal to the square root of $n$ divide $n$. If you want to check that a number between 900 and 950 is prime with this rule, what is the largest prime divisor you need to test

the largest divisor is less than the square root of that number

Step-by-step explanation:

Pick any number between 900 and 950 . For example I choose 937 . Now taking the square root of 937 would give 30.61

So divide 937 with all the primes less  than 30.61

937/2, 937/3, 937/5,937/29

29 would be the largest divisor which is less than the square root of 937 .

29< 30.61

But if you check 937 does not divide wholly with any of the primes hence it is a prime number itself.

If any number such 925 is chosen and it gets divided wholly by another prime like 5

925 /5= 185  so it is not a prime number

#15. square

step-by-step explanation:

because quadrilatural (idk how to spell it) means somthing that is not 3d or like, equal sides (or somthing like that   you know what i meanz)

hope this halps!

bai!

pls refer ro the top for answer