Solve the division 1. (x^3y^3 + x^2y^3 – xy^4 + xy) ÷ xy
and this if possible
ii) 14p^3q^4 – 28p^4q^3 ÷ (-7p^2q^3)

The equation to solve is:

(x3y3+x2y2+xy+1)ydx+(x3y3−x2y2−xy+1)xdy=0

t3−t2−t+1t3+t2+t+1dt=dxx

any more help just ask :)

yes

step-by-step explanation:

yes

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.