Find the area that is enclosed by the parabola y = x²-3x line y = 2x and line y = -x

39/2

Step-by-step explanation:

First, we find the points of intersection (POI) of the curve and one of the lines:

x²-3x=2x

x²-5x=0

x(x-5)=0

x=0,5

Next, we find the POI of the curve and the second line:

x²-3x=-x

x²-2x=0

x(x-2)=0

x=0,2

To better visualize this, you can go on Desmos.

The area enclosed by all three lines is going to be the area enclosed by the curve and y=-x () subtracted from the area enclosed by the curve and y=2x ().

Since 2x is greater than the curve in the interval [0,5],

=

Solving this, you would get 125/6.

Since -x is greater than the curve in the interval [0,2],

=

Solving this, you would get 4/3.

=125/6-4/3=39/2

Hope this helps!

answer: c

because if you look at the chart you can see a pattern and compare it to the question he simplify out your

but i think the formula is f(x)=6x