A plastics manufacturer has developed a new type of plastic trash can and proposes to sell them with an unconditional 6-year warranty. To see whether this is economically feasible, 20 prototype cans are subjected to an accelerated life test to simulate 6 years of use. The proposed warranty will be modified only if the sample data strongly suggests that fewer than 90% of such cans would survive the accelerated test. After the accelerated life test on the 20 prototype cans, 13 survive. Does this indicate that the proposed warranty should be modified? Use =0.05.

since -3.73 is less than 1.645, we reject H₀.    

Therefore this indicate that the proposed warranty should be modified

Step-by-step explanation:

Given that the data in the question;

p" = 13/20 = 0.65

Now  the test hypothesis;

H₀ : p = 0.9

Hₐ : p < 0.9

Now lets determine the test statistic;

Z = (p" - p ) / √[p×(1-p)/n]

= (0.65 - 0.9) /√[0.9 × (1 - 0.9) / 20]  

= -0.25 / √[0.9 × 0.1 / 20 ]

= -0.25 / √0.0045

= -0.25 / 0.067

= - 3.73

Now given that a = 0.05,

the critical value is Z(0.05) = 1.645 (form standard normal table)

Now since -3.73 is less than 1.645, we reject H₀.    

Therefore this indicate that the proposed warranty should be modified

i get you, what you should do is think of the positive things that would come out of it. it will make yours parents proud and raise your grade. you should always try and if you can't focus tell the teacher.

a. 32 degrees

step-by-step explanation:

here we have to use the rule.

m∠e = 1/2 (major arc - minor arc)

m∠e = 1/2 (212 - 148)

m∠e = 1/2 (64)

m∠e = 32 degrees

answer: a. 32 degrees

you