Mathematics, 26.12.2020 14:00 teesoprettyy

Find the perimeter quickly I will give 25 point
5 the question and the mivelenious one

Find the perimeter quickly I will give 25 point5 the question and the mivelenious one

Answers: 2

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Answer from: alissa64

Step-by-step explanation:

Question (5)

Perimeter of sector APQR = AP + arc(PQR) + AR

AP = AR = 7 cm

Formula to get the length of arc(PQR) = $\frac{\theta}{360}(2\pi r)$

Here, r = radius of the sector

θ = Angle by the arc PQR at the center of the circle

arc(PQR) = $\frac{45}{360}(2\pi )(7)$

= $\frac{630\pi }{360}$

= $\frac{7\pi }{4}$

= 4.497 ≈ 4.50 cm

Perimeter of APQR = 2(7) + 4.50

= 18.50 cm

Perimeter of shaded region = BP + arc(BCD) + arc(PQR) + DR

arc(BCD) = $\frac{\theta}{360}(2\pi r)$

= $\frac{45}{360}(2\pi )(3.5)$

= 0.875π

≈ 2.75 cm

Perimeter of shaded region = 2(3.5) + 2.75 + 4.50

= 14.25 cm

Difference in perimeter of APQR and perimeter of shaded region = 18.50 - 14.25

= 4.25 cm

Perimeter of APQR is 4.25 cm more than the perimeter of the shaded region.

Miscellaneous question

Perimeter of remaining lamina = 2(21) + Length of arc of the remaining portion

= 42 + $\frac{\theta}{360}(2\pi r)$

= 42 + $\frac{(360-120)}{360}(2\pi )(21)$

= 42 + 28π

= 42 + 87.96

= 129.96

≈ 130 cm

Answer from: Quest

The answer is the first one

Answer from: Quest

$a_1 = 1$ , and

$a_{n+1} = a_n + (n + 1)$ for $n \ge 1$

step-by-step explanation:

we can analyze the pattern at which the terms increase. let us denote $a_1 = 1$ , $a_2 = 3$ , $a_3 = 6$ , so that we can call

1 the 1st term, 3 the 2nd term, 6 the 3rd term,etc.

note the following:

from the 1st term (1) to the 2nd term (3), we go up by 2,from the 2nd term (3) to the 3rd term (6), we go up by 3from the 3rd term (6) to the 4th term (10), we go up by 4, andfrom the 4th term (10) to the 5th term (15), we go up by 5.

the pattern: to get the next term value, we just add the next term number (e.g. 1st, 2nd, to the previous term value (term values are the given numbers in the question, 1, 3, 6, 10, 15,

from $a_1 = 1$ , to get to $a_2 = 3$ , we add $2(=1+1)$

from $a_2 = 3$ , to get to $a_3 = 6$ , we add $3 (=2+1)$

etc.

we need to form a recursive formula, a formula that has the next term as a function of the previous term. so a possible recursive formula can be

$a_1 = 1$ , and $a_{n+1} = a_n +(n + 1)$ for $n \ge 1$

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Find the perimeter quickly I will give 25 point
5 the question and the mivelenious one
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