X^2-x-6=0
Solve for X
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there are two values for 'x'; one = 3 and the other is -2

Step-by-step explanation:

two answers because this is a quadratic equation which, when graphed, will produce a u-shaped curve which intersects the x-axis in the two coordinates listed above

x^2 - x - 6 = 0

use the 'foil' method backwards to find out two factors of 6 which will produce a -6 when multiplied and negative one when added; they are:

(x - 3)(x + 2)=0

pls ask

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?