the lenght of car is 4.2m correct to 1 decimal place write down upper bound and the lower of bound of the lenght of this car ?

The upper pound is 4.25 m and the lower bound is 4.15 m

4.15 m ≤ 4.2 m < 4.25 m

Step-by-step explanation:

Let us solve the question

∵ The length of the car corrected to 1 decimal place

→ 1 decimal place means tenth

∴ It corrected to the tenths place which is 0.1

→ Divide it by 2

∵ 0.1 ÷ 2 = 0.05

∴ The limit is 0.05 m

→ To get the lower bound subtract 0.05 from the length of the car

∵ The length of the care is 4.2 m

∴ The lower bound = 4.2 - 0.05

∴ The lower bound = 4.15 m

→ To get the upper bound add 0.05 to the length of the car

∵ The length of the care is 4.2 m

∴ The upper bound = 4.2 + 0.05

∴ The upper bound = 4.25 m

∴ 4.15 m ≤ 4.2 m < 4.25 m

∴ The upper pound is 4.25 m and the lower bound is 4.15 m

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42

it’s supposed to be -4+45=41

step-by-step explanation: