Find an equation in slope-intercept form of the line that has slope 2 and passes through point A(9,-2)

y = 2x-20

Step-by-step explanation:

Slope intercept form of a line is

y = mx+b  where m is the slope and b is the y intercept

y = 2x +b

Substitute the given point in

-2 = 2 ( 9) +b

-2 =18+b

Subtract 18 from each side

-2 -18 = 18+b-18

-20 = b

The equation is y = 2x-20

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

what are the answer choices given for this problem?