Rectangle ABCDABCDA, B, C, D is graphed in the coordinate plane. The following are the vertices of the rectangle: A(-4, -2)A(−4,−2)A, left parenthesis, minus, 4, comma, minus, 2, right parenthesis, B(-2, -2)B(−2,−2)B, left parenthesis, minus, 2, comma, minus, 2, right parenthesis, C(-2, 7)C(−2,7)C, left parenthesis, minus, 2, comma, 7, right parenthesis, and D(-4, 7)D(−4,7)D, left parenthesis, minus, 4, comma, 7, right parenthesis.
What is the area of rectangle ABCDABCDA, B, C, D?
square units

18 square units.

Step-by-step explanation:

Vertices of rectangle ABCD are,

A → (-4, -2)

B → (-2, -2)

C → (-2, 7)

D → (-4, 7)

Since, area of a rectangle is given by the formula,

Area of a rectangle = Length × Width

                                = AB × BC

To get the measure of length and width we will use the formula,

d =

AB = = 2 units

BC = = 9 units

Area of the rectangle ABCD = 2 × 9 = 18 square units

Therefore, 18 square units is the area of the rectangle ABCD.

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

the awnser is visionary