A rock is thrown upward from a bridge that is 24 feet above a road. The rock reaches its maximum height above the road 0.79 seconds after it is thrown and contacts the road 3.06 seconds after it was thrown. Write a function ff that determines the rock's height above the road (in feet) in terms of the number of seconds tt since the rock was thrown.

dude it’s f(t) = [Error]

Step-by-step explanation:

cut 138 centimeters off

step-by-step explanation:

250-112 = 138

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.