A 20-dirham note is 13 cm long. How many such notes need to be placed one after the other without overlapping to cover a length of 1 1 2 m?

861 (approx)

Step-by-step explanation:

It is given that there is a note of 20 dirham. The 20 dirham note is 13 cm long. And we have to place the 20 dirham notes to cover a length of 112 m without overlapping the notes.

We know that :

100 cm = 1 m

∴ 13 cm = 0.13 m

In order to cover a length of 112 m, we have to divide 112 by 0.13, i.e.

= 861 (approx)

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18