Matter is in a liquid state when its temperature is between its melting point and its boiling point. Suppose that some substance has a melting point of -49.90 degrees Celsius and a boiling point of 324.47 degrees Celsius. What is the range of temperatures in degrees Fahrenheit for which this substance is not in a liquid state? (Hint: C=5/9(F-32)) Express the range as an inequality and in interval notation.

answer:   y=2x-3

step-by-step explanation:

8(4)^8=72^feet to say that the total can conclude to 8(4) which as you know would mean 8 x 4. that equals 32w. 32^ could make a 72 answer as well. but your coefficent will remain w so your answer is 72w.

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4y < -4

we need to isolate y. we can do this by simply dividing both sides by 4.

4y ÷ 4 > -4 ÷ 4

simplify.

y > -1

5 - y > 0

once again, we need to isolate y, so we can start off by subtracting 5 from both sides.

5 - y - 5 > 0 - 5

simplify.

-y > -5

divide both sides by -1.

** remember that when dividing any side by a negative, you must switch the sign! **

-y ÷ -1 < -5 ÷ -1

simplify.

y < 5

~hope i ! ~