What is the equation of the line that passes through the point
(-3,-5) and is parallel to the line
2x+3y=15

y = (-2/3)*x -7

Step-by-step explanation:

2x+3y=15

3y = -2x + 15

y = (-2/3) *x + 5

slope for parallel line should be -2/3 too

pass (-3 , -5)      y = mx + b      b = y - mx = (-5) - ((-2/3) * (-3))

b = -5 - 2 = -7

parallel line: y = (-2/3)*x -7

i believe the answer is letter c) 8

step-by-step explanation: