After the announcement of a sale, a bookstore sold 1/2 of all its books in stock. On the following day, this bookstore sold 4,000 more books. Now only 1/10 of the number of books in stock before the sale remain in the store. How many books were in stock before the announcement of the sale?

155

Step-by-step explanation:

Let p represent the number of paperback books sold. Then p-60 is the number of hardback books sold. Total revenue will be the sum of products of price and quantity.

 2.99p +3.49(p-60) = 795 . . . . . an equation for total revenue

 6.48p -209.40 = 795.00 . . . . . simplify

 6.48p = 1004.40 . . . . . . . . . . . . add 209.40

 1004.40/6.48 = p = 155 . . . . . . divide by the coefficient of p

The owner sold 155 paperback books.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.