what is the equation of the line in point slope form that has a slope of -7/8, going through point (12,-3)

y= (-7/8)x +7.5

Step-by-step explanation:

We know that the form for the equation of a line is

y= mx+b, with m being the slope, so our equation is

y=(-7/8)x+b. As b should be a constant, we need to find b. Plugging (12,-3) in, we have -3 = (-7/8)(12)+b =  -10.5+b. Adding 10.5 to both sides, we get b= 7.5, making our equation

y= (-7/8)x +7.5

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.