Chapter 1: Quadrati END-OF-CHAPTER REVIEW EXERCISE 1
1
A curve has equation y = 2xy+ 5 and a line has equation 2x + 5y = 1.
The curve and the line intersect at the points A and B. Find the coordinates of the midpoint
of the line AB

mid point of AB (0.5 , 0)

Step-by-step explanation:

2x + 5y = 1      2x = 1 - 5y

y = 2xy+ 5 = (1 - 5y)*y + 5 = y - 5y² + 5

y-y = y - 5y² + 5 - y = - 5y² + 5

0 = - 5y² + 5

5y² = 5

y² = 1

y = 1 or y = -1

if y = 1       x = 1/2 (1 - 5) = -2   .... point A (-2 , 1)

if y = -1      x = 1/2 (1 + 5) = 3   ..... point B (3 , -1)

mid point of AB (x' , y') :  x' = 1/2 (x₁ + x₂) = 1/2 (-2 + 3) = 1/2

                                        y' =  1/2 (y₁ + y₂) = 1/2 (-1 + 1) = 0    

the graph in the attached figure

step-by-step explanation:

we have

using a graphing tool

the graph in the attached figure

the roots are ( x-intercepts) x=-0.5,x=1,x=3

the y-intercept is the point (0,3)

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~