13 points for anyone that can solve the issue
please show working

Step-by-step explanation:

1.  u^2 = x^(p+q)

v^2 = x^(p-q)

Show that logx u + logx v = p

From statement 1

p + q = logx u^2 = 2 logx u   (by the laws of logs)

Similarly:

p - q = logx v^2 = 2 logx v

So 2 logx U + 2 logx v  = p+q + (p - q)

2 (logx u + logx v)  =  2p

logx u + logx v = p.

Also 2(logx u - logx v)  =  p+q - (p - q) = 2q

and logx u - logx v = q.

2.  ∛(8a^3b^3) / √(1/25 * a^4b^7)* (16√(a^4b^6))^-1/2

= 2ab / 1/5a^2b^7/2 *  (16a^2b^3)^-1/2

= 2ab / 1/5a^2b^7/2 * 1 / 4ab^3/2

= 2ab / 4/5 a^3 b^5

=  5ab / 2 a^3 b^5

= 5/(2a^2b^4).

Step-by-step explanation:

homozygous. one is homozygous, while two is heterozygous.