The perimeter of a rectangle is 162 inches. what are the dimensions of the rectangle if the length is 7 times than 3 times the width?

3.68 inches × 77.28 inches

Step-by-step explanation:

Given that,

The perimeter of a rectangle is 162 inches.

Let the width is b.

ATQ,

Length = 7 times than 3 times the width

l = 7(3b) = 21b ...(1)

The perimeter of a rectangle is given by :

P = 2(l+b)

Put all the values,

162 = 2(21b+b)

81 = 22b

b = 3.68 inches

Put the value of b in equation (1)

l = 21b

= 21 (3.68)

= 77.28 inches

Hence, the dimensions of the rectangle are 3.68 inches × 77.28 inches

all but the second one

step-by-step explanation:

cuz that one goes over 180

mark brainliest