In a large population, 61 % of the people have been vaccinated. If 3 people are randomly selected, what is the probability that AT LEAST ONE of them has been vaccinated

0.94

Step-by-step explanation:

Computation for what is the probability that AT LEAST ONE of them has been vaccinated

Based on the information given this is a binomial Distribution therefore Let;

Number of people represent n= 3 people

Population represent p = .61

Using this formula

Probability(AT LEAST ONE vaccinated) = 1 - [ 1*(1-Population vaccinated^People randomly selected)]

Let plug in the formula

Probability(AT LEAST ONE vaccinated) = 1 -[1*(1-.61^3)]

Probability(AT LEAST ONE vaccinated) = 1 - [1×(1-.61^3)]

Probability(AT LEAST ONE vaccinated) = 1 - (1×.39^3)

Probability(AT LEAST ONE vaccinated) = 1 - 0.059319

Probability(AT LEAST ONE vaccinated) = 0.940681

Probability(AT LEAST ONE vaccinated) = 0.94

Therefore the probability that AT LEAST ONE of them has been vaccinated is 0.94

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8

you est gay to much man grow some bollas also man kcuf off you little harry p u s s y. stupid