A vanilla thickshake is $2 more than a fruit juice. If 3 vanilla thickshakes and 5 fruit juices cost $30, determine their individual prices using simultaneous elimination

vanilla thickshake = $5

fruit juice = $3

USING ELIMINATION METHOD

Let the price of vanilla thickshake = x

Let the price of fruit juice = y

Given that a vanilla thickshake is $2 more than a fruit juice.

so

Given that If 3 vanilla thickshakes and 5 fruit juices cost $30.

So the system of equations

Arrange equation variables for elimination

so

so the system of equations becomes

solve 8y = 24 for y

Divide both sides by 2

Divide both sides by 3

Therefore,

                                              2ND METHOD

Step-by-step explanation:

As a vanilla thickshake is $2 more than a fruit juice.

Given that 3 vanilla thickshakes and 5 fruit juices cost $30.

3(Vanilla thickshakes) + 5(fruit juice) = 30

3(x+2) + 5x = 30

3x+6+5x=30

8x+6=30

8x=30-6

8x=24

x = 3

Thus,

x intercept = (-1,0)   (4,0)

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐