A plane leaves London where the tempretaure outside is 17 C. The plane rises to a height where the tempreture outside is -43 C.
The tempreture decreases by 2 C with every increase of 300 m in height.
The maximum height of plane is

First you find the difference in temperature. Final temperature minus initial temperature. -43-17=-60 So for every 300m temp will minus 2C.

There's a difference of -60, how many -2 is in -60? So -60÷(-2)= 30. 30 times 300m = 9000m or 9km.

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180