In the given image, △ADF≅△DBE and DF=BE. A triangle A B C has three line segments D E, E F and F D. Point D roughly bisects side A B, point E roughly bisects side B C, and point F roughly bisects side A C. Which statement would be required to show that DF=1/2 BC?

what is the information provided?

step-by-step explanation:

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb