Find the measure of QS.

S9T 10 R 21 F 4x+5 Q

A. 35 B, 20 C. 27 D. 29

C. 27

Step-by-step explanation:

((4x + 5) + 10)*10 = (21 + 9)*9 (two secants intersecting)

(4x + 5 + 10)*10 = (30)*9

(4x + 15)*10 = 270

40x + 150 = 270

40x = 270 - 150 (subtraction property of equality)

40x = 120

Divide both sides by 40

40x/40 = 120/40

x = 3

✔️QS = (4x + 5) + 10

Plug in the value of x

QS = 4(3) + 5 + 10

QS = 12 + 5 + 10

QS = 27

isocolese triangle

we know that the line connect a and b is the hyptonuse

so first find the hypotonuse length using the distance formula, call the length c

since it is an isocolese triangle, the lengths of the legs are the same

using pythagorean theorem,

in this case, a=b since isocolese triangle so we get

or

we can find c so we can find the distances

we know that if we draw 2 circles, each has center at a and b, and find where they intersect, we can the 2 possible locations for c

if a has center at (xa,ya) and b has center at (xb,yb), then we can solve where

and

intersect to find where they intersect

i'm not going to put an example because i have to go to class. i hope this explanation is enough