Two people decided to race. One of the cars is 10 meters north of the start line 5 seconds into the race. After 15 seconds, the car is 25 meters north of the start line. Calculate the average velocity of the car.

The average velocity of the car is 1.5 m/s

Step-by-step explanation:

The given parameters are;

The displacement of one of the cars north of the start after 5 seconds = 10 meters

The displacement of the car north of the start after 15 seconds = 25 meters

The average velocity of the cars is given as follows;

Where;

Δx = The change in the displacement of the car = 25 m - 10 m = 15 m

Δt = The corresponding amount of the change in time 15 s - 5 s = 10 s

By substituting the known values of Δx and Δt in the equation for the average velocity of the car, , we have;

∴ The average velocity of the car, = 1.5 m/s

i really dont know

step-by-step explanation:

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