In the diagram shown, CDEF is a trapezium,
ABCF is a rectangle,
BD = 9 cm,
AB = 6 cm,
EF = 3 cm,
Perimeter of ABCF = 20 cm.
6 cm
Calculate the area of trapezium CDEF.
You must show all your working.

1/2 * (5+3) * 6 = 24 cm^2

Step-by-step explanation:

Perimeter is 20

and it's a rectangle so 2x + 12= 20

x is 4 so one of parallel side of trapezium is 9-4 or 5 then just apply formula for area of trapezium

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

853.3

step-by-step explanation: