An LA football player can run 20 yards in 3.4 seconds. Whicl equation could be
used to find y, the number of yards the
football player can run in a second?
A 20y = 3.4 C 3.4y = 20
B 3.4 - y = 20 D 20 + y = 3.4

1260=3*6*7*10=3^2*2^2*7*5 perfect cude = 3^3*2^

step-by-step explanation:

look at the picture.

1.

ef : ab = 2 : 3

gf : cb = 2 : 3

gh : cd = 2 : 3

he : da = 2 : 3

2.

∠a ≅ ∠e

∠b ≅ ∠f

∠c ≅ ∠g

∠d ≅ ∠h

3.

use pythagorean theorem:

the length of the abcd trapezoid sides:

|ab| = 3 cm

|bc| = 10 cm

|cd| = 3(3) cm = 9 cm

|da| = 8 cm

the perimeter of abcd = 3 + 10 + 9 + 8 = 30 cm

the ratio of perimeters of the tarapezoids is equal 2 : 3.

substitute:

      cross multiply

      divide both sides by 3

2x=70  

x=70/2

x=35

thats the answer

step-by-step explanation:

16 b

17 d

step-by-step explanation:

16.

amount = 3250(1.06) ^3.5 = 3985.23

17.

m = 9pn

divide both sides by 9n: -

p = m/9n