You want to obtain a sample to estimate how much parents spend on their kids birthday parties. Based on previous study, you believe the population standard deviation is approximately σ

=

62.5

dollars. You would like to be 95% confident that your estimate is within 3 dollar(s) of average spending on the birthday parties. How many parents do you have to sample?

The number of parents spend their kids birthday parties

'n' = 1667

Step-by-step explanation:

Explanation:-

Given standard deviation of the Population = 62.5

Given the estimate error = 3 dollars

Level of significance =0.05

Z₀.₀₅ = 1.96

The margin of error defined by

cross multiplication , we get

3√n = 1.96 X 62.5

 √n = 40.833

Squaring on both sides, we get

n = 1667.34



The number of samples are 'n' = 1667

it's d.

step-by-step explanation:

because: -1(4x + 1y) +2 (1x-3y) distribute each number into the parenthesis.

then you would get: -4x - 1y + 2x -6y combine like terms

and get: 2x -7y

hope my answer has you if not then i'm sorry.

step-by-step explanation:

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