For the picture of the kite below, how would you prove that triangle BCE is congruent to triangle DCE if ∠1 is congruent to ∠2 and ∠3 is congruent to ∠4? Write a proof plan to answer.

∆ adc is congruent to ∆ abc by asa congruence rule where CA is common side,

so CD and CB are congruent therefore angle cbe is same as angle cde

so ∆ bce and ∆ dce are congruent by ASA congruence rule

40 x 50 = 2000

step-by-step explanation:

i cant answer this, theres no table. sorry man

step-by-step explanation: