Is this the X factor method and how would you do it?

Work Shown:

4x^2 - 8x - 192

4(x^2 - 2x - 48)

4(x - 8)(x + 6)

We see that (x - 8) is one factor

To factor x^2-2x-48 into (x-8)(x+6), we need to find two numbers that

Through trial and error you should find the two values are -8 and 6 since

Another approach is to use the quadratic formula to solve x^2-2x-48 = 0. You should find that the two roots are x = 8 and x = -6.

Those two roots lead to the equations x-8 = 0 and x+6 = 0.

Then use the zero product property to get (x-8)(x+6) = 0

This shows that x^2-2x-48 factors to (x-8)(x+6)

step-by-step explanation:

5×5×5+2(8)÷2(2)+3(3)

15+16÷4+9

31÷13

do 31÷13 and u will get ur answer