A department store's survey suggests that 76% of shoppers buy food, 49% buy clothes, and 28% buy both food and clothes Suppose a shopper is selected from the store at random and learn that they buy clothes. What is the
probability that the shopper also buys food?
027
0.39
0.57
0.64

0.57

Step-by-step explanation:

Given that:

food = f ; c = clothes

P(f) = 0.76

P(C) = 0.49

P(fnC) = 0.28

Suppose a shopper is selected from the store at random and learn that they buy clothes. What is the probability that the shopper also buys food?

P(f Given C) = P(f | C)

P(f | c) = p(fnC) / p(C)

P(f | c) = 0.28 / 0.49

P(f | c) = 0.5714

P(f | c) = 0.57

answer:  

step-by-step explanation:

odd numbers are only divisible by 1 and itself.

even numbers are divisible by more than 1 and itself.

for example 6 is even because it is divisible by more than 1 and its self. 1 x 6= 6 ; 2 x 3= 6

and 7 is odd because only 7 x 1 equals seveb