4. Find the value of the real number y such that (3+2i)(1 + iy)
is :
(a) real
(b) imaginary

Step-by-step explanation:

(3 + 2i)(1 + iy)

= 3 + (3y + 2)i - 2y (because i² = -1)

For this to be real, (3y + 2) = 0. => y = -2/3

For this to be imaginary, y can be any real or complex number (except -2/3)

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: