The distance a spring will stretch varies directly with how much weight is attached to the spring if a spring stretches 11 inches is 75 pounds attached how far will it stretch with 65 pounds attached round to the nearest 10th of an inch

the weight that attached to the spring is 9.5 inches

Step-by-step explanation:

The computation is shown below:

inches per pound is

= 11 inches ÷ 75 pounds

Now for 65 pounds, it would be

=  11 inches ÷ 75 pounds × 65 pounds

= 9.5 inches

Hence, the weight that attached to the spring is 9.5 inches

The same is relevant and considered

you need to show us the graph.

step-by-step explanation:

d 25 pi/6

step-by-step explanation:

the diameter is 10 inches

the radius is 1/2 of the diameter or 5 inches

the area of the circle is

a = pi r^2

  = pi 5^2

  = 25 pi

the slice is 60 degrees of the entire circle.

60 degrees out of 360   60/360 = 1/6

the area of the slice is 1/6 of the circle

a slice = 1/6 a circle

a slice = 1/6 * 25 pi