Given that P(x)=x^5-8x^3-x^2+2, what is the remainder when it is divided by x-5?

2102

Step-by-step explanation:

The polynomial function P(x)=x^5-8x^3-x^2+2, if it is divided by x-5, first we need to get x from the divisor as shown

since d(x) = x-5

x-5 = 0

x = 5

Substitute x = 5 into the expression to get the remainder

P(x)=x^5-8x^3-x^2+2

P(5)=(5)^5-8(5)^3-(5)^2+2

P(5) = 3125-1000-25+2

p(5) = 2100+2

P(5) = 2102

Hence the remainder is 2102

d

step-by-step explanation:

by observation, we can see that the the graph is simply the graph of y = |x| that has been shifted 4 units downwards and 3 units to the left.

we can recognize in choice d :

y = | x + 3 |   - 4 (rewriting in general form)

y = | x - (- 3) |   - 4

the "-4 " term means   that the graph has been shifted by 4 units in the negative y direction

the "-3 " term means   that the graph has been shifted by 3 units in the negative x direction

this matches our observation of the graph described above.