In Algebra you learned that Difference of Perfect Squares is x^2 - 25 = (x+5)(x-5) Is there a way to factor the sum of perfect squares? ex: x^2 + 25 = (?)(?)

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  yes, if you allow complex numbers; no, if you don't

Step-by-step explanation:

The sum of squares can be considered to be the difference of squares, where one of the squares is negative. The negative square is the square of an imaginary number, so the factoring involves imaginary numbers.

  x^2 +25 = x^2 - (-25) = x^2 -(5i)^2

  = (x -5i)(x +5i) . . . . factoring in the complex numbers

There is no factoring in real numbers.

i dont get the question

step-by-step explanation:

answer: bea's uncle is 25 years old.

step-by-step explanation:

given the equation , we can say that the variable "x" represents the age of bea's uncle. then to find his age, we need to solve for "x":

we must add 15 to both sides of the equation:

now we need to divide both sides of the equation by 3:

therefore, we can conclude that bea's uncle is 25 years old.