Jim has 44 coins using only nickels and dimes totaling $2.95. how many of each coin does he have?

Nickels = 29

Dimes = 15

Step-by-step explanation:

Let

Nickels = x

Dimes = y

x + y = 44 (1)

0.05x + 0.10y = 2.95 (2)

From (1)

x = 44 - y

Substitute x = 44 - y into (2)

0.05x + 0.10y = 2.95

0.05(44 - y) + 0.10y = 2.95

2.2 - 0.05y + 0.10y = 2.95

-0.05y + 0.10y = 2.95 - 2.2

0.05y = 0.75

y = 0.75 / 0.05

= 15

y = 15

Substitute y = 15 into (1)

x + y = 44

x + 15 = 44

x = 44 - 15

= 29

answer: 19 is   2

step-by-step explanation: i just looked at your answer and wrote it down

answer:      

step-by-step explanation: