The volume of a rectangular box is 1600 cubic inches. The height of the box is 8 inches and the length of the box is 2 times longer than the width of the box. What is the width of the box "IN FEET FT"?

0.833 feets

Step-by-step explanation:

Given that:

Volume of box = 1600

Heigh of box (H) = 8 inches

Let:

Width of box (W) = x

Length of box (L) = 2x

Volume of box = (Height * width * length)

1600 = (8 * x * 2x)

1600 = 16x²

x² = 1600/16

x² = 100

x = sqrt(100)

x = 10 inches

Hence, width of box in feet:

1 inch = 0.0833 feets

10 inches = (10 * 0.0833) feets

= 0.833 feets

21.4 i did it already for s1

step-by-step explanation:

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3