Helene invested a total of $1,250 in two simple-interest bank accounts. One account paid 4% annual interest; the other paid 7% annual interest. The total amount of interest she earned after 1 year was $71.
Find the amount invested in each account.

$550 was invested in the 4% account while $700 was invested in the 7% account

Step-by-step explanation:

Let the amount invested in each account be $x and $y respectively

The sum of these two is $1,250

Mathematically;

x + y = 1250 •••••(i)

Now, let’s work with the interest rate;

4% of x + 7% of y = 71

4x/100 + 7y/100 = 71

Multiply through by 100

4x + 7y = 7100 •••••(ii)

From i;

x = 1250-y

Substitute this into ii

4(1250-y) + 7y = 7100

5000 - 4y + 7y = 7100

3y = 7100-5000

3y = 2100

y = 2100/3

y = 700

Recall;

x + y = 1250

700 + x = 1250

x = 1250 - 700

x = 550

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

teleportation

step-by-step explanation: