Write the equation of a line that is perpendicular to y=7/5x+ 6 and that passes through the point (2,-6).

Given that,

The equation of line is y=7/5x+ 6 and that passes through the point (2,-6).

To find,

The equation of line that is perpendicular to the given line.

Solution,

The given line is :

y=7/5x+ 6

The slope of this line = 7/5

For two perpendicular lines, the product of slopes of two lines is :

Equation will be :

y=-5x/7+ b

Now finding the value of b. As it passes through (2,-6). The equation of line will be :

So, the required equation of line is :

y=-5x/7+ (-32/7)

a. turk and mcalister

b. howard, mission, and market

c. yes. since streets end some do not cross yet are not parallel to others. example: mcalister and 5th

step-by-step explanation:

parallel lines are lines which do not intersect ever and look a lot like railroad tracks. turk, mcalister and golden gate are examples of these.

intersect are streets which cross each other and a car on one can reach the other. howard, mission, and market intersect with 6th.

skew lines are lines which neither intersect nor are parallel. these lines exist here because some streets end and never intersect another like mcalister and 5th.

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step-by-step explanation: