A quality assurance inspector at a donut factory, checks for product quality using a random sample of 7 donuts from a batch of 38, with 14 cake donuts and 24 glazed donuts. Let p^ be the proportion of cake donuts in the sample. Is the 10% condition met in this case?

Is the Normal condition met in this case?

A: The 10 percent condition states that the population is greater than 10 times the sample, or 10n. In other words, the sample size must be no more than 10 percent of the population. In this problem, the sample size is 7, and the population is 38. This means that 38>10n, or 38>10 times 7, or 70. 38 is not greater than 70, therefor the 10 percent condition is not met in this case. 

B: In this problem, p, or the population proportion is 14/38. The conditions of normality are that n times p and n times 1-p are both greater than 5. n=38 and p, as stated, equals 14/38. This means that n times p equals 14, and n times 1 minus p equals 24, which are both greater than 5. This means that both of the normality condition have been met.

Step-by-step explanation:

the answer is 13 cm

there would only be 50 odd numbers between 1 and 100 so therefor there would be 50 even so that would only be 50 odd numbers.