Mei has 8 jars of soup. each jar contains 300 millimeters of soup. what is the smallest pot mei can use to heat all the soup.

Pan of 2.4 liters can be used.

Step-by-step explanation:

Since Mei has 8 jars of soup and each jar contains 100 milliliters of soup.

We have to calculate the smallest pot Mei can use to heat all the soup.

Total volume of soup = Number of jars × Volume of one jar (Volume of soup in one jar) = 8×300 = 2400 ml.

∵ 1000 ml is equal  to 1 liters

∴ 1 ml is equal to 1/1000 liters

∴ 2400 ml soup is = 2400×(1/1000) = 2.4 liters

So a pan with volume of 2.4 liters can be used.

b is 38 degrees.

a is 52 degrees.

this is because if b is 38 and a is 14 degrees more than b than 38+14=52 and 52+38=90 degrees. hope this .