You can rent a car via two options. Option A charges $20 per day plus $0.10 per mile. Option B charges $0 per day, but $0.50 per mile. How many miles must you drive in one day for option A to be cheaper?

50 miles

Step-by-step explanation:

Step one

given data

let the total charge be y and the number of miles be x

Option A charges $20 per day

plus $0.10 per mile.

y= 20+0.1x1

Option B charges $0 per day,

but $0.50 per mile

y= 0.5x2

equate 1 and 2 we have

20+0.1x=0.5x

20=0.5x-0.1x

20=0.4x

divide both sides by 0.4

x= 20/0.4

x=50 miles

10.416 m/s

step-by-step explantion:

distance=100m

time= 9.6s

average speed=100/9.6

=10.416 m/s