A quantity with an initial value of 8100 decays continuously at a rate of 0.95% per year. What is the value of the quantity after 96 months, to the nearest hundredth?

20163.299

Step-by-step explanation:

Initial value = 8100

Rate r = 0.95% = 0.0095

t = 96 month

Therefore, Value of the quantity after 39 decades = Initial value*e^(rt)

= 8100*e^(0.0095*96)

= 8100*e^(0.912)

= 8100*2.48929615041

= 20163.298818321

= 20163.299

So, the value of the quantity after 96 months is 20163.299

the answer is simply just 6n add the two together as they have an n