math The newly elected president needs to decide the remaining 3 spots available in the cabinet he/she is appointing. If there are 15 eligible candidates for these positions (where rank matters), how many different ways can the members of the cabinet be appointed

2730 ways

Step-by-step explanation:

Given that,

There are 15 eligible candidates for these positions.

The newly elected president needs to decide the remaining 3 spots available in the cabinet he/she is appointing.

It is a concept based on permutations.

Put n = 15 and r = 3

Hence, 2730 ways can the members of the cabinet be appointed

answer: 2x + 2 − 2 = 10 − 2; subtraction property of equality

step-by-step explanation:

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068