Consider the following frequency table representing the scores on a test. Scores on a Test

Class Frequency
40–43 7
44–47 7
48–51 7
52–55 8
56–59 4

Required:
a. Determine the lower class boundary for the fifth class.
b. Determine the upper class boundary for the second class.
c. Determine the class width of each class.
d. Determine the number of scores between 39.5 and 55.5

(a)56

(b)47

(c)3

(d)29

Step-by-step explanation:

From the given frequency

(a) Fifth class is 56-59.

    The lower class boundary for the fifth class is 56.

(b) Second class is 44-47.

    The upper-class boundary for the second class is 47.

(c) Class width = 47-44 = 3, 47-44 = 3.

(d) Number of scores between 39.5 and 55.5 is

    =7 + 7+ 7 + 8 =29

well my understanding of this question is they want you to use the y=14.1x -2.3 and put the coordinates they gave you onto the line segment of   y=14.1x -2.3

step-by-step explanation:

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w