Consider a set of data in which the sample mean is 73.4 and the sample standard deviation is 4.9. Calculate the z-score given that x

This question is incomplete, the complete question is;

Consider a set of data in which the sample mean is 73.4 and the sample standard deviation is 4.9. Calculate the z-score given that x  = 69.5.

Round your answer to two decimal places.

the z-score is -0.80

Step-by-step explanation:

Given that;

mean μ = 73.4

standard deviation σ = 4.9

x = 69.5

z-score = ?

z = (x - μ) / σ

we substitute

z =  (69.5 - 73.4) / 4.9

z = -3.9 / 4.9

z = - 0.7959 ≈ -0.80    { 2 decimal places }

Therefore, the z-score is -0.80

i am unable to solve this problem

step-by-step explanation:

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.