Three consecutive even have a sum of 168. what is the value of the largest integer?

Let, the integers = x,(x+2),(x+4)

x+x+2+x+4 = 168

3x+6 = 168

3x = 162

x = 162/3 = 54

Largest number, x+4 = 54+4 = 58

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

what is the original number? you forgot to add it.