How many ways can a person toss a coin 14 times so that the number of tails is between 11 and 13 inclusive

Step-by-step explanation:

Probability is the possibility for an event to occur or not to occur.

The formula for a combination is:

n choose r = n! / (r! x (n-r)!)

Given

n=14

r= 11 to 13

Hence, we shall add up the cases for 11 through 13.

nCr

14C11 + 14C12 + 14C13

14!/11!(14-11)! + 14!/12(14-12)! + 14!/13(14-13)!

= 14!/11!•3! + 14!/12!•2! + 14!/13!•1!

= 14*13*12*11!/11!•(3*2*1) + 14*13*12!/12!•(2*1) + 14*13!/13!•(1*1)

= 2184/6+182/2+14/1

= 364+91+14

= 469 ways

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

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